
Arturo O. answered 07/17/17
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I gave you the steps to solving this problem in your previous posting. Just convert units and plug in the numbers.
You are given density ρ and mass m. Get volume from
V = m/ρ
But since
V = πr2h = πd2h/4,
(where d is the diameter, which you get from the gauge of the wire), you can combine the 2 equations above and get
h = [4 / (πd2)] V = [4 / (πd2)] (m/ρ)]
Final equation for h:
h = [4 / (πd2)] (m/ρ)]
At this point, all you have left to solve is an elementary arithmetic problem. Just plug in the numbers in appropriate units.
You are given density ρ and mass m. Get volume from
V = m/ρ
But since
V = πr2h = πd2h/4,
(where d is the diameter, which you get from the gauge of the wire), you can combine the 2 equations above and get
h = [4 / (πd2)] V = [4 / (πd2)] (m/ρ)]
Final equation for h:
h = [4 / (πd2)] (m/ρ)]
At this point, all you have left to solve is an elementary arithmetic problem. Just plug in the numbers in appropriate units.