here is an example

f(n)=1X2^{n-1}

here is an example

f(n)=1X2^{n-1}

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Because any number multiplied by 1 is itself...1 X n = n, you could restate this function as f(n)=2^{(n-1)}.

Therefore

f(0)=2^{-1}=1/2=.5.

f(1)=2^{0}=1

f(2)=2^{1}=2

etc.

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## Comments

for me, the question is not stated clearly enough --- what are the values of "n" --- could you possibly re-phrase the question?

if the values of n are 0, -1, -2, -3, etc., then we would have the following:

I wonder if the following would help: f(0) = 2^(0-1) = 2^(-1) = 1/2 = 0.5

f(-1) = 2^(-1-1) = 2^(-2) = 1/(2^2) = 1/4 = 0.25

f(-2) = 2^(-2-1) = 2^(-3) = 1/(2^3) = 1/8 = 0.125

etc., etc., etc.