here is an example f(n)=1X2^{n-1} 1/16/2013 | Carson from Farmington, UT | 1 Answer | 0 Votes Mark favorite Subscribe Comment Comments for me, the question is not stated clearly enough --- what are the values of "n" --- could you possibly re-phrase the question? if the values of n are 0, -1, -2, -3, etc., then we would have the following: I wonder if the following would help: f(0) = 2^(0-1) = 2^(-1) = 1/2 = 0.5 f(-1) = 2^(-1-1) = 2^(-2) = 1/(2^2) = 1/4 = 0.25 f(-2) = 2^(-2-1) = 2^(-3) = 1/(2^3) = 1/8 = 0.125 etc., etc., etc. 1/17/2013 | Herb K. Comment
for me, the question is not stated clearly enough --- what are the values of "n" --- could you possibly re-phrase the question? if the values of n are 0, -1, -2, -3, etc., then we would have the following: I wonder if the following would help: f(0) = 2^(0-1) = 2^(-1) = 1/2 = 0.5 f(-1) = 2^(-1-1) = 2^(-2) = 1/(2^2) = 1/4 = 0.25 f(-2) = 2^(-2-1) = 2^(-3) = 1/(2^3) = 1/8 = 0.125 etc., etc., etc. 1/17/2013 | Herb K.
Because any number multiplied by 1 is itself...1 X n = n, you could restate this function as f(n)=2^{(n-1)}. Therefore f(0)=2^{-1}=1/2=.5. f(1)=2^{0}=1 f(2)=2^{1}=2 etc. 2/14/2013 | Ben H. Comment
Comments
for me, the question is not stated clearly enough --- what are the values of "n" --- could you possibly re-phrase the question?
if the values of n are 0, -1, -2, -3, etc., then we would have the following:
I wonder if the following would help: f(0) = 2^(0-1) = 2^(-1) = 1/2 = 0.5
f(-1) = 2^(-1-1) = 2^(-2) = 1/(2^2) = 1/4 = 0.25
f(-2) = 2^(-2-1) = 2^(-3) = 1/(2^3) = 1/8 = 0.125
etc., etc., etc.