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Select the approximate values of x that are solutions to f(x)=0, where f(x)=-6x^2+7x+6

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2 Answers

With this question, we use the quadratic formula.
 
x = (-b±√b2- 4ac)/2a
     (-7±√72 - 4x-6x6)/2x-6
     (-7±√49 - -144)/-12
     (-7±√193)/-12
     (-7 + 13.89)/-12   and (-7 - 13.89)/-12
          -0.57               and       1.74
 
The answer is (-0.57, 1.74)
This is Quadratic:
 
  Use Quadratic formula:
 
   f(X ) = - 6 X^2 + 7X +6 
 
 
    X = -b/2a ±√( -b/2) ^2 - 4ac) /2a 
 
     X = -7 / -( -12) ± (√[ (-7/12) ^2 - 4 ( -4) ( 4)/-12 ] =
 
        = 7/12 ±√(7^2 +144)/12
 
       = ( -0.57, 1.74)