P=2RT/3b what is dp/dT? (differentiation) I know the answer is 2R/3b but can't see the steps to get there

The derivative of a fraction is: y=x/k => y'= (k(dx/dx) - x(dk/dx))/k

^{2}. In this case the second term is zero so the answer will be y' = (dx/dx)/kP=2RT/3b

(dP/dT)= (2T)/3b

I do not see anything to any power.

## Comments

dF(x) = x^b dx

= x^(b-1) / b