Arthur D. answered • 04/23/14

Effective Mathematics Tutor

let B=# of bicycles

let A=# of tandem bicycles

let T=# of tricycles

2B+2A+3T=269 (wheels)

1B+2A+1T=135 (seats)

1B+1A+1T=118 (front handlebars)

multiply 3rd equation by 2

2B+2A+2T=236

subtract this equation from 1st equation

T=33 tricycles

replace T by 33 in 2nd and 3rd equations

1B+2A+33=135

1B+1A+33=118

subtract these equations

A=17 tandem bicycles

substitute into the second equation:

B+34+33=135

B+67=135

B=68 bicycles

check:68+34+33=135 seats

68+17+33=118 handlebars

2(68)+2(17)+3(33)=136+34+99=269 wheels