I have No idea on what to do.

"x in quadrant 2" means the terminal ray of the angle x is in quadrant 2.

If a and b are positive numbers, then (-a,b) is a point in quadrant 2.

We know any point can also be represented as (r cos(x), r sin(x) ), so:

(r cos(x), r sin(x) ) = (-a,b)

sin(x) = b/r

cos(x) = -a/r = -3/4

a = 3, r = 4

r^2 = a^2 + b^2

16 = 9 + b^2

b^2 = 16-9 = 7

b = √(7)

sin(x) = b/r = √(7)/4

cos(x) = -a/r = -3/4

cos(x) = -a/r = -3/4

tan(x) = sin(x)/cos(x) = -√(7)/3

cot(x) = 1/tan(x) = -3√(7)/7

sec(x) = 1/cos(x) = -4/3

csc(x) = 1/sin(x) = 4√(7)/7