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Physics-Specific Heat and Heat of Fusion

1. Given that the specific heat of water is 1.00 cal/(g*C), what is the specific heat in Joules/(kg*K)?
2. If 700 grams of a metal requires 95 calories of energy to raise its temperature by 10 Kelvin, what is its specific heat?
3. How much heat is gained or lost when 250 grams of ice melt?

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Daniel H. | Knowledgeable and Patient Math and Science TutorKnowledgeable and Patient Math and Scien...
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Hi Meg,
To convert from cal/(g*C) to J/(kg*K), we just need to find a conversion factor for specific heat. There is really no mathematical way to do this other than to look in a physics or chemistry book and find a conversion factor. After doing this, you will see that 1 cal/(g*C) is equal to 4,186 J/(kg*K).
To find the specific heat of a material, first look at the units. There is energy per unit mass per unit temperature. So if we are given an amount of energy appllied to an object, its mass and how much the temperature of the object rises, we can calculate its specifc heat by dividing the energy by both the mass and the temperature, but don't forget to keep the units as they are:
Specific heat of the metal = (95 cal)/(10 K * 700g) = 0.014 cal/(g*K)
To find how much energy it requires to melt 250 grams of ice, we will need what is called the Latent Heat of Melting for ice. This is the amount of heat required to change unit mass of a solid into unit mass of a liquid at a constant temperature. Again, using a reference, the latent heat of melting for ice is found to be 334 kJ/kg. So the energy required to melt one kg of ice is 334 kJ. The amount of energy required to melt 0.250 kg of ice is then:
334 * 0.250 = 83.5 kJ