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Not necessarily. In a parallelogram, if you construct a diagonal you will create two congruent triangles. But in the given quadrilateral, if you construct a diagonal opposite to both of the equal angles, you create two triangles that only have SSA congruency; so the two triangles are not congruent and the quadrilateral is not a parallelogram.

Wups; I read it wrong. I read it as though "pair of" wasn't there. Michael is right.

OTOH, the language might be interpreted as a kite.

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