Michael C. answered • 04/22/17

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Lets take the cuboid; surface area is (2*16 + 2*30)8 + 30 * 16 = 1216 square inch

lets take the cylindrical portion; pi.r

^{2}(area of two half circles)^{ }+ pi.r*30 (half circle circumference times length)= 3.14 (8)

^{2 }+3.14 * 8 * 30 = 955Total surface area = 1216 + 955 =

**2171 (I)**in^{2 }; be careful as H is in cubic inch which is volume, area is square inch.Michael C.

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