Rekha N.

# need help on probability:

A study involved married husbands and wives
in prime time 60% husbands are watching TV, when husband is watching, 30% of the time wife is also watching.When husband is not watching, 10 % of the time wife is watching TV

1.Probabilty that wife is watching Tv while husband is also watching TV

2.Probability that wife is watching TV during Prime time:

Please explain how to compute this rounding to three decimal places

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Table_Data,     B,   B`
A 10,  40
A' 40, 20
P(A|B)
P(A|B')
P(A'|B')

Are events A and B independent?

## 2 Answers By Expert Tutors

By:

Tutor
4.9 (34)

~20 Years Accounting Tutoring Experience

Kay G.

tutor
You got the .04 by taking 10% of .40.  i.e. P(wife|husband') * P(husband').
But you left the .30 alone, rather than taking P(wife|husband) * P(husband).
In other words, it's inconsistent.

The problem says this:
"when husband is watching, 30% of the time wife is also watching.When husband is not watching, 10 % of the time wife is watching TV"
but you have treated one as a condition and one as not.

You've not shown where that .04 came from.

You've determine they're independent but have not shown where you came to this conclusion.

Report

03/21/14

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