Rekha N.

asked • 03/20/14

need help on probability:

A study involved married husbands and wives
in prime time 60% husbands are watching TV, when husband is watching, 30% of the time wife is also watching.When husband is not watching, 10 % of the time wife is watching TV
 
1.Probabilty that wife is watching Tv while husband is also watching TV
 
2.Probability that wife is watching TV during Prime time:
 
Please explain how to compute this rounding to three decimal places
 
--------------------------------------------------------------------------------------------------------------------------
 
Table_Data,     B,   B`
                 A 10,  40
                 A' 40, 20
P(A|B)
P(A|B')
P(A'|B')
 
Are events A and B independent?
 
 
 
 

2 Answers By Expert Tutors

By:

Kay G.

tutor
You got the .04 by taking 10% of .40.  i.e. P(wife|husband') * P(husband').
But you left the .30 alone, rather than taking P(wife|husband) * P(husband).
In other words, it's inconsistent.
 
The problem says this:
"when husband is watching, 30% of the time wife is also watching.When husband is not watching, 10 % of the time wife is watching TV"
but you have treated one as a condition and one as not.
 
You've not shown where that .04 came from.
 
You've determine they're independent but have not shown where you came to this conclusion.
 
 
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03/21/14

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