Select the appropriate values of x that are solutions to f(x)=0, where f(x)=2x^2+2x+8

Hi Valerie,

f(x)=0

f(x)=2x²+2x+8

2x²+2x+8=0

x²+x+4=0

By using the quadratic formula,

x = -1±√(1)²-4(1)(4)

2(1)

= -1±√-15

2

=-1/2±i√15/2