Three consecutive whole numbers are such that if they be divided by 5,3 and 4 respectively, the sum of the quotient is 40. What are the numbers?

here is how I do it:

1) "Three consecutive whole numbers": n, n+1, n+2;

2) "if they be divided by 5,3 and 4 respectively": n/5, (n+1)/3, (n+2)/4

3) "the sum of the quotient is 40": 40= n/5 + (n+1)/3 + (n+2)/4

4) solve n: 40x5x4x3= nx3x4 + (n+1) x 5 x4 + (n+2) x5X3

--> n=50

Answer: these numbers are: 50, 51, 52

Double check:

50/5=10

51/3=17

52/4=13

10+17+13=40