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the complete hotel bill was $68 (room and tax). If the sales tax is 9%, what was the cost for the room before the tax?

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3 Answers

Here is another approach with a lot of detail. 
 
Let x = cost of the room before taxes (since this is what we want to find, let it be x.  This is good practice for all word problems)
9% tax is equivalent to .09 (removing the percent sign and replacing with 9/100  because 9% = 9/100)
$tax = .09x
 
68 it total cost of the room plus total tax simply put:
 
$68 = $room + $tax (note that tax in this equation is the dollar amount, not the percentage of tax)
 
So that means
 
x+ (.09x) = 68  or  ( × + (9/100)x = 68)
 
1x+ .09x = 68
1.09x = 68  (divide both sides by 1.09)
 
x = 68/1.09
 
x = 62.385 (round to the nearest 100th because it's money. Money only goes out 2 decimal places.  So round UP because the last number is 5)
 
x = $62.39  FINAL ANSWER
 
check your work:
 
$tax = 62.39*.09 = 5.62
$room + $tax = $68
$62.39 + $5.62 = 68.01 (close enough.. because of rounding it's a little off... but still correct)
 
 
 
The reason Bam's answer is wrong is because the 9% is based off of the cost of the room BEFORE taxes.  This is a common mistake in calculating taxes.  Always remember that taxes are based off the ORIGINAL cost, not final.
 
Hope that helps.

Zakiyyah

Comments

Not true Bam . Problem Explicitly says:
 
   The bill was issued for $68 ( Room and TAX) , means Room Plus Tax , and the bills normally issued on total amount,including tax.
room and tax minus tax = room before tax
 
$68 - 9% of $68 is the cost of the room before tax : that is $68 x (1 - 0.09) = $68 x (0.91) = $61.88
 
ATTENTION! PARVIZ'S ANSWER IS NOT CORRECT!  

Comments