The period of a 4.202 m long pendulum on planet Zenix is 4.115 s. What is g on planet Zenix?

Question

Report your answer in:
in terms of m/s2. Do not include units in your answer. They will be assumed to be m/s2.
to a precision of hundreths of a m/s2. Use a format like #.## in your answer.
to an accuracy of 0.02 m/s2. Answers within 0.02 m/s2 of the correct answer will be tolerated.

Answer 1

T=2pi√(L/g)

4.115=2pi√(4.202/g)

√(4.202/g)=4.115/(2pi)

4.202/g=(0.655)^2

g=4.202/0.429

g=9.795