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Juan H.

asked • 02/04/17

Use the shell method to find the volume of the region below the graph of f(x)=cos(x^2) [0,1/2sqrt(pi)] is rotated about the y-axis

find the volume generated by revolving the region between them about the x-axis: f(x)=2 and g(x)=cos(x) [0,Pi/2]

1 Expert Answer

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Kenneth S. answered • 02/04/17

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