This is the question: x+y=2

3x-2y=-9

This is the question: x+y=2

3x-2y=-9

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Inglewood, CA

multiply the first eqn by 2

2(x + y = 2) gives 2x + 2y = 4

add to 2nd eqn to eliminate the y

5x = -5 so x = -1

substitute in either original eqn

using the 1st eqn, y = 2-x = 2-(-1) = 3

Middletown, CT

Hi Tracey;

x+y=2

3x-2y=-9

The coefficient of x in the second equation is 3.

The coefficient of y in the second equation is -2.

Let's take the first equation and multiply both sides by either coefficient. I randomly choose 3...

3(x+y)=(2)(3)

3x+3y=6

Let's subtract one equation from the other...

3x+3y=6

-(3x-2y=-9)

0+5y=15

Please remember that subtracting a negative number is the same as adding a positive number...

3y--2y=3y+2y=5y

6--9=6+9=15

5y=15

Let's divide both sides by 5...

(5y)/5=15/5

Let's input this result into either equation to establish the value of x. I randomly choose the first. I will use its original form...

x+y=2

x+3=2

Let's subtract 3 from both sides...

x+3-3=2-3

Let's take the second equation and verify the results...

3x-2y=-9

[(3)(-1)]-[(2)(3)]=-9

-3-6=-9

-9=-9

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