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(4,-6) , x+2y=5

Write the slope intercept form for an equation of the line that passes through the given point and is parallel to the graph of each.
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1 Answer

Hi Gabby;
The equation is in standard form...
Ax+By=C, A>0
Slope is -A/B
x+2y=5
Slope is -1/2.
The parallel line has the same slope.
Let's use point-slope formula...
y-y1=m(x-x1)
Let's plug-in (4,-6)...
y--6=(-1/2)(x-4)
Subtracting a negative number is the same as adding a positive number, --6 is +6...
Multiplying a negative number by a negative number has a positive result, (-1/2)(-4) is 2...
y+6=(-1/2)x+2
Subtract 6 from both sides...
y+6-6=(-1/2)x+2-6
y=(-1/2)x-4
The equation is now in slope-intercept format...
y=mx+b
m is the slope.
b is the y-intercept, the value of y when x=0.
y=(-1/2)x-4
This is standard form...
(1/2)x+y=-4