_{1}=m(x-x

_{1})

**y=(-1/2)x-4**

**(1/2)x+y=-4**

Write the slope intercept form for an equation of the line that passes through the given point and is parallel to the graph of each.

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Hi Gabby;

The equation is in standard form...

Ax+By=C, A>0

Slope is -A/B

x+2y=5

Slope is -1/2.

The parallel line has the same slope.

Let's use point-slope formula...

y-y_{1}=m(x-x_{1})

Let's plug-in (4,-6)...

y--6=(-1/2)(x-4)

Subtracting a negative number is the same as adding a positive number, --6 is +6...

Multiplying a negative number by a negative number has a positive result, (-1/2)(-4) is 2...

y+6=(-1/2)x+2

Subtract 6 from both sides...

y+6-6=(-1/2)x+2-6

The equation is now in slope-intercept format...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

y=(-1/2)x-4

This is standard form...

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