John S.

asked • 12/06/16# Use the divergence theorem to evaluate I=s∫∫(4x+3y^2+Z)dS

Use the divergence theorem to evaluate I=

_{S}∫∫(4x+3y^{2}+z)dS,Where s is unit sphere x

^{2}+y^{2}+z^{2}=1.
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Caleb M.

^{2}+Z)dSUse the divergence theorem to evaluate I=S∫∫(4x+3y

^{2}+z)dS,Where S is unit sphere x

^{2}+y^{2}+z^{2}=1."^{2}+z)"^{2}+z)=4x^{2}, ∂f/∂y(4x+3y^{2}+z)=4y^{2}, and ∂f/∂z(4x+3y^{2}+z)=4z^{2}.^{2}+ 4y^{2}+4z^{2}"^{2}+y^{2}+z^{2}=1"^{2}+y^{2}+z^{2}=1" and spherical coordinates conversion goes like this "∫∫∫ρsin(φ) dρdθdφ."^{2}+y^{2}+z^{2}=1," "x^{2}+y^{2}+z^{2}" [ρ^{2}]; so ∫∫∫[ρ^{2}]ρsin(φ)dρdθdφ^{2}(sin(φ))dρdθdφ^{2}12/31/16