The difference between the length and width of a rectangle is 7 centimeters. Find the dimensions of the rectangle if it's perimeter is 50 centimeters

Hi Alex;

perimeter=[2(length)]+[2(width)]

first dimension...x

second dimension...x+7

50=[2(x)]+[2(x+7)]

50=2x+2x+14

50=4x+14

Subtract 14 from both sides...

50-14=4x+14-14

36=4x

Divide both sides by 4...

36/4=(4x)/4

9=x

first dimension....9

second dimension...16

Let's check our work.

50=2(9+16)

50=2(25)

50=50