**i need some help on some questions can you help**

Hi Kayla;

Linear equations are typically represented in

**slope-intercept format**of...y=mx+b

m is the slope, the change-of-y divided by the change-of-x.

b is the y-intercept, the value of y when x=0.

For example, if we are provided two points of a line...

(0,5)(5,15)

Our first priority is to establish slope...

(y-y

_{1})/(x-x_{1})(5-15)/(0-5)=-10/-5=2

slope is 2...

y=2x+b

The y-intercept, b, is provided as (0,5)...

y=2x+5

Another

**format**is**standard**...Ax+By=C, neither A nor B equal zero and A is greater than zero.

The slope is -A/B. The slope of 2 would be-(2/1) or (2/-1). The negative one is in the denominator because A must be greater than zero...

2x-1y=C

2x-y=C

To calculate C, we would enter either coordinate. I randomly select the second of (5,15)...

[(2)(5)]-15=C

10-15=C

-5=C

2x-y=-5

The the other point is the y-intercept of (0,5). We can use this to verify. Such verification can be performed whether or not it is the y-intercept.

[(2)(0)]-5=-5

-5=-5

The other

**formula**is**point-slope**...y-y

_{1}=m(x-x_{1})We will use either point and this will expand into slope-intercept formula. I randomly select the point of (0,5)...

y-5=2(x-0)

y-5=2x

Let's add 5 to both sides...

5+y-5=2x+5

y=2x+5

Let's use the other point, (5,15) to verify results...

15=[(2)(5)]+5

15=10+5

15=15

I HOPE THIS HELPS!

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