Brian M.

asked • 11/07/16

The parabolas y=x^2, y=x^2+1, y=(x-2)^2, y=(x-2)^2+1

The parabolas y=x^2, y=x^2+1, y=(x-2)^2, y=(x-2)^2+1 Intersectto form a curvilinear quadrilateral R. The change of variable u=y-x^2, v=y-(x-2)^2 map R onto a square in the uv-plane. Use the jacobian of the inverse transformation to compute the area of R.

Kendra F.

Check to make sure the question is correct. currently all parabolas are facing up, at least one should be reversed (-x or -x2), otherwise there is no upper bound, no shape and no area to compute. (1≤y<infinity)
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11/07/16

Mark M.

tutor
Did you graph the four parabolas?
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11/07/16

1 Expert Answer

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Al P. answered • 11/10/16

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