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# A baseball player has a batting average of 0.315. Estimate how many hits he will get in his next 43 at bats

A baseball player has a batting average of 0.315. Estimate how many hits he will get in his next 43 at bats.

### 3 Answers by Expert Tutors

Arthur D. | Effective Mathematics TutorEffective Mathematics Tutor
5.0 5.0 (7 lesson ratings) (7)
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A batting average of 0.315 means 315 hits out of 1000 at-bats or 315/1000=63/200 which means 63 hits out of 200 at-bats or 34 hits out of 108 at-bats which equals 34/108=0.3148 which rounds to 0.315.
You can set up a proportion: 315/1000=x/43 where x=# of hits.
Cross multiply to get 315*43=1000*x
13,543=1000*x
13,543/1000=x
13.545=x
He will get about 13-14 hits in his next 43 at bats-13/43=0.302 and 14/43=0.325
The simplest way to solve the problem is to multiply 0.315*43=13.545 or about 13-14 hits
Look at it this way; if he is batting 0.300 that means he gets 3 hits in every 10 at-bats. In 43 at-bats there are
4 tens so he should get at least 3*4=12 hits !
Bryan B. | Math Tutor in or near FolsomMath Tutor in or near Folsom
5.0 5.0 (7 lesson ratings) (7)
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Batting avg is just a percentage. If instead of 0.315 he or she had a 0.100 batting average they would get a hit 10% of the time.

If they had 43 more at bats then you would expect them to get 4.3 hits (43 * 10%) or 43 * 0.100.

Please respond if that doesn't make sense.
Julian M. | Accounting, Finance, Business, Statistics and Mathematics TutorAccounting, Finance, Business, Statistic...
5.0 5.0 (20 lesson ratings) (20)
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Given that a baseball player has a batting average of .315, this means that out of 1000 times at bat, the player would get a hit 315 times, or 315/1000.  So if this same player steps to the plate 100 more times, you would expect them to get a hit 31.5 times or 100 *.315.  So in your instance, if a player has 43 more at bats, then they would have a hit 43 * .315 or ____!  In other words, the batting average of .315 is a percentage representing the percent of time a player hits the ball.  I hope this helps.