An open box with its base having a length twice its width is to be constructed with 600 square cm of material. Find its dimensions that maximize the volume.
so I am asked to maximize l*w*h = 2w^2*h
I solved for h in terms of w
I plugged it into l*w*h and solved for w
2w*w*(600-2w^2)/(6w) = 0
(1200w^2-4w^4)/6w = 0
I know this is not the answer
where did I go wrong?