Find the equation of a line through the points (-2,1) and (3,6)
Hi John;
(-2,1) and (3,6)
First, let's establish slope.
Slope is the change-of-y divided by the change-of-x.
slope=(y-y_{1})/(x-x_{1})
slope=(1-6)/(-2-3)
slope=-5/-5
slope=1
Let's take one point and use the point-slope formula. I randomly select the first point, (-2,1)
y-y_{1}=m(x-x_{1})
y-1=1(x--2)
Subtracting a negative number is the same as adding a positive number...
y-1=x+2
Let's add 1 to both sides...
1+y-1=x+2-1
y=x+3
Let's apply the other point, (3,6), to verify...
6=3+3
6=6