Peter G. answered 09/29/16
Tutor
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Two approaches: (note we are adding two functions, and composing a third, x/2. It might help to rewrite h and g using u instead of x first, so as not to confuse with the x in the input x/2: this gives h(u)=-2u, and g(u)=3u+1)
1. Combine h and g second:
h(x/2) = -2*(x/2) = -x
g(x/2) = 3*(x/2) + 1 = (3x+2)/2
Now (h + g)(x/2) = -x + (3x+2)/2
= (-2x + 3x + 2)/2
= (x+2)/2
OR
2. Combine h and g first:
(h+g)(u) = -2u + 3u + 1 = u + 1
Now (h + g)(x/2) = (x/2) + 1 = (x+2)/2
Note here I used u instead of x, but you can just replace the u's with x's to match the problem as given.
Peter G.
tutor
combine fractions:
(3x/2) + 1 = (3x/2) + 2/2 = (3x+2)/2
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09/29/16
Malik D.
09/29/16