Find the integral of 3/x^2 dx from -1 to 1. Answer: nonexistent Please show all your work. 1/20/2014 | Sun from Los Angeles, CA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
1 1 ∫ 3dx /x^2 = - 3 l =( - 3/1 ) - ( -3/ -1 ) = -3 -3 = -6 -1 X l-1 1/20/2014 | Parviz F. Comment Comments There is an infinite discontinuity at x=0. 1/20/2014 | Christopher D. Comment
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