This is a set of review problems, and I don't remember how to start. The firat problem looks like this:

f(x) = 3x + 2

This is a set of review problems, and I don't remember how to start. The firat problem looks like this:

f(x) = 3x + 2

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Logan, UT

The domain of a function is the numbers on the x coordinate that the function can be. The range is the same, but for the y axis.

So for the function you gave, if the domain is all numbers between -1 and 3, you plug in those numbers

So for the function you gave, if the domain is all numbers between -1 and 3, you plug in those numbers

ƒ(-1) = 3x + 2 → 3(-1) + 2 = -5

ƒ(3) = 3x + 2 → 3(3) + 2 = 11

and the output is the range.

In this case, the domain would be all numbers between -1 and 3, and the range would be all numbers between -5 and 11

ƒ(3) = 3x + 2 → 3(3) + 2 = 11

and the output is the range.

In this case, the domain would be all numbers between -1 and 3, and the range would be all numbers between -5 and 11

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