This is a set of review problems, and I don't remember how to start. The firat problem looks like this:

f(x) = 3x + 2

This is a set of review problems, and I don't remember how to start. The firat problem looks like this:

f(x) = 3x + 2

Tutors, please sign in to answer this question.

Logan, UT

The domain of a function is the numbers on the x coordinate that the function can be. The range is the same, but for the y axis.

So for the function you gave, if the domain is all numbers between -1 and 3, you plug in those numbers

So for the function you gave, if the domain is all numbers between -1 and 3, you plug in those numbers

ƒ(-1) = 3x + 2 → 3(-1) + 2 = -5

ƒ(3) = 3x + 2 → 3(3) + 2 = 11

and the output is the range.

In this case, the domain would be all numbers between -1 and 3, and the range would be all numbers between -5 and 11

ƒ(3) = 3x + 2 → 3(3) + 2 = 11

and the output is the range.

In this case, the domain would be all numbers between -1 and 3, and the range would be all numbers between -5 and 11

Gilant P.

Miss Gil: Cares & Gets Results - Regents, SAT & NYS ELA & Math Exams

Jamaica, NY

4.8
(1420 ratings)

Wesley L.

Premier MIT Math Tutor and SHSAT/SAT/ACT Specialist

New York, NY

5.0
(211 ratings)

Larry G.

Algebra/Geometry/SAT Tutor

Bronx, NY

4.9
(141 ratings)

- Algebra 2 2842
- Algebra 4042
- Math 7183
- Prealgebra 142
- Geometry 1472
- Algebra Help 886
- Algebra Word Problem 2028
- Math Help 4168
- Word Problem 3995
- Precalculus 1248

## Comments