Aiden A. answered • 10/07/16

Tutor

New to Wyzant
Aiden A. Marietta, GA

ANALYSIS

We want to mix 2 solutions - a 60%(.6) and a 75%(.75) saline solution to get a target solution.

Our target solution = 100 fluid oz, 72%(.72)concentration.

SOLUTION

Let the Fluid ounces of the 60% solution = x ( Note: Always equate what you are looking for to x.)

Therefore, .................the 75% solution = 100-x ( This follows because our mixture of the two solutions is 100)

**.60x + .75(100-x) = .72(100)**

**.60x + 75**-

**.75x = 72**

**.15x = 3**

**x = 3/.15 = 20.**

Amy F.

09/23/16