Last question for the day I appreciate the help.

Hi again Joe;

y= x+3

I assume the point provided is NOT (5+0) but rather (5,0).

This equation is in the form of...

y=mx+b

m is the slope.

b is the y-intercept.

The slope is 1.

Any line

**parallel**to it also has a slope of 1, but different y-intercept.y=x+b

Let's plug-in the one point provided...

0=x+5

-5=x

y=x-5