My hardest question, open-ended plzz help.

Hi again Joe;

y=2x+3

This equation is in the slope-intercept form of...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

m=2

The slope of the perpendicular line is -1/2.

Let's plug-in the slope of -1/2 as well as the one point provided.

However, let's NOT use the slope-intercept form but rather the point-slope formula...

(y-y

_{1})=m(x-x_{1})(y-4)=(-1/2)(x-3)

y-4=(-1/2)x+1.5

Let's add 4 to both sides...

4+y-4=(-1/2)x+1.5+4

y=(-1/2)x+5.5