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Write an equation of the line that is perpendicular to y=2x+3 and passes through (3,4)

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1 Answer

Hi again Joe;
y=2x+3
This equation is in the slope-intercept form of...
y=mx+b
m is the slope.
b is the y-intercept, the value of y when x=0.
m=2
The slope of the perpendicular line is -1/2.
Let's plug-in the slope of -1/2 as well as the one point provided.
However, let's NOT use the slope-intercept form but rather the point-slope formula...
(y-y1)=m(x-x1)
(y-4)=(-1/2)(x-3)
y-4=(-1/2)x+1.5
Let's add 4 to both sides...
4+y-4=(-1/2)x+1.5+4
y=(-1/2)x+5.5