_{1})=m(x-x

_{1})

It is really hard and I don't get it someone answer quick

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Hi Mikk;

The point-slope formula is...

(y-y_{1})=m(x-x_{1})

m=slope

(y-5)=(1/2)(x--1)

Subtracting a negative number is the same as adding a positive number.

(y-5)=(1/2)(x+1)

y-5=(1/2)x+(1/2)

Let's add 5 to both sides...

5+y-5=(1/2)x+(1/2)+5

y=(1/2)x+(5 1/2)

The equation is now in slope-intercept form of...

y=mx+b, b is the y-intercept, the value of y when x=0.

The standard form of the equation would be...

Ax+By=C, neither A nor B equal zero, and A is greater than zero.

y=(1/2)x+(5 1/2)

Let's subtract (1/2)x from both sides...

-(1/2)x+y=(1/2)x+(5 1/2)-(1/2)x

(-1/2)x+y=5 1/2

A is not greater than zero. To render it such, we will multiply both sides by -1...

-1[(-1/2)x+y)=-1(5 1/2)

(1/2)x-y=-5 1/2

There is a nice way to access an equation called the point-slope form of a line. This form looks like :

y - y_{1 }= m (x-x_{1})

All you do is plug the slope and your point into the equation to get your line... like this:

y - 5 = ½ (x - -1) and then simplify...

ANSWER: y - 5 = ½ (x + 1)

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