It is really hard and I don't get it someone answer quick
Hi Mikk;
The point-slope formula is...
(y-y_{1})=m(x-x_{1})
m=slope
(y-5)=(1/2)(x--1)
Subtracting a negative number is the same as adding a positive number.
(y-5)=(1/2)(x+1)
y-5=(1/2)x+(1/2)
Let's add 5 to both sides...
5+y-5=(1/2)x+(1/2)+5
y=(1/2)x+(5 1/2)
The equation is now in slope-intercept form of...
y=mx+b, b is the y-intercept, the value of y when x=0.
The standard form of the equation would be...
Ax+By=C, neither A nor B equal zero, and A is greater than zero.
y=(1/2)x+(5 1/2)
Let's subtract (1/2)x from both sides...
-(1/2)x+y=(1/2)x+(5 1/2)-(1/2)x
(-1/2)x+y=5 1/2
A is not greater than zero. To render it such, we will multiply both sides by -1...
-1[(-1/2)x+y)=-1(5 1/2)
(1/2)x-y=-5 1/2