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Find the value of ALL the other five trigonometric functions, given tanx= 4/11, secx<0.

Thanks for the help! If you could please show all your work? Thanks again!

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Jane B. | Master's degree in Education. Focus on success for all students.Master's degree in Education. Focus on s...
4.8 4.8 (5 lesson ratings) (5)
Kirill and Felice gave good answers, but I wanted to add this to eliminate any confusion.
We can only use trig functions with right triangles, so you have to use Pythagorean's Theorem to solve for the hypotenuse: a2+b2=c2. a and b = 4 and 11, in either order, according to the problem. Therefore, c2=137; c=sqrt137.
I hope that fills in any gaps. Kirill and Felice covered the rest of the explanation.
Kirill Z. | Physics, math tutor with great knowledge and teaching skillsPhysics, math tutor with great knowledge...
4.9 4.9 (174 lesson ratings) (174)
Since sec(x)<0 and tan(x)>0, angle is in the third quadrant.
Felice R. | Need Help in Math and Science - Engineer willing to helpNeed Help in Math and Science - Engineer...
4.0 4.0 (1 lesson ratings) (1)
Well if we use the trigonometric functions
sin X = opposite / hypotenuse
cos X = adjacent / hypotenuse
tan X = opposite/ adjacent
csc X = hypotenuse / opposite
sec X = hypotenuse/adjacent
ctn X = adjacent/opposite
We know that the hypotenuse = sqrt(adjacent+ opposite2)
from your given tan X = 4/11 we could say the the opposite was 4 and adjacent was 11
so our hypotenuse would be sqrt(112 + 42) = sqrt (121+16) = sqrt(137) = 11.7
so your sin X = opp/hyp = 4/11.7
fill in the rest for the other 4 functions