George and Bill left town A for town B at the same time. George was riding a bicycle at a constant speed, while Bill was driving a car. Bill traveled 5 times faster than George. Bill's car broke halfway, and the rest of the way to the town B Bill traveled by foot with a speed equal to half of the George's bicycle speed. Who got to B first: George or Bill?

George Speed - X

Bills Speed - 5X

Bills speed by foot - X/2

d- distance from A-B

X = d/t1 5X + X/2 =d/t2

11X/2 = d/ t2

t1= d/X ---------------- time it takes Bill to go from A to B

t2 = d/ (11X/2)---------- Time it will take George to go from A to B

t1= d/X

t2=2d/11

t1 > t2 , Therefore Bill reaches earlier.

Note : The formula used was

Speed * ( time it would take) = distance traveled.