I am trying to pull out equations from word problems

P = 2L + 2W

P ≥ 692

L+ W ≥ 346

L+31≥ 346

L ≥315

This is simply an inequality problem.( ≥ ) should be used for at least ( minimum value),

I am trying to pull out equations from word problems

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Woodland Hills, CA

P = 2L + 2W

P ≥ 692

L+ W ≥ 346

L+31≥ 346

L ≥315

This is simply an inequality problem.( ≥ ) should be used for at least ( minimum value),

Tracy, CA

In a rectangle opposite sides are equal

perimeter = 2(length + Width)

2(l + W) must greater than or equal to 692

L + W must be greater than or equal to (692/2)346

L + 31 must be greater than or equal to 346

there fore L must be greater than or equal to (346 - 31) 315

:)

Roseville, CA

Good morning! Recall that perimeter of a rectangle is the sum of the lengths of all sides, so:

P= L + L + W + W, or P + 2L + 2W

If the width is 31 and total perimeter is at least 692, then the minimum would be:

692 = 2L + 2(31), or 692 = 2L + 62

Subtract 62 from both sides:

630 = 2L

Divide both sides by 2:

315 = L

Remember that the perimeter is at least 692; therefore the length would be at least 315 cm

Hope this helps

Mike

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