Parviz F. answered • 12/16/13

Mathematics professor at Community Colleges

Harvey B.

asked • 12/16/13I am trying to pull out equations from word problems

Follow
•
3

Add comment

More

Report

Parviz F. answered • 12/16/13

Tutor

4.8
(4)
Mathematics professor at Community Colleges

P = 2L + 2W

P ≥ 692

L+ W ≥ 346

L+31≥ 346

L ≥315

This is simply an inequality problem.( ≥ ) should be used for at least ( minimum value),

Amarjeet K. answered • 12/16/13

Tutor

4.6
(8)
Professional Engineer for Math and Science Turoring

In a rectangle opposite sides are equal

perimeter = 2(length + Width)

2(l + W) must greater than or equal to 692

L + W must be greater than or equal to (692/2)346

L + 31 must be greater than or equal to 346

there fore L must be greater than or equal to (346 - 31) 315

:)

Michael W. answered • 12/16/13

Tutor

5.0
(345)
Experienced Biology teacher/tutor/nestor

Good morning! Recall that perimeter of a rectangle is the sum of the lengths of all sides, so:

P= L + L + W + W, or P + 2L + 2W

If the width is 31 and total perimeter is at least 692, then the minimum would be:

692 = 2L + 2(31), or 692 = 2L + 62

Subtract 62 from both sides:

630 = 2L

Divide both sides by 2:

315 = L

Remember that the perimeter is at least 692; therefore the length would be at least 315 cm

Hope this helps

Mike

Robert J. answered • 12/16/13

Tutor

4.6
(13)
Certified High School AP Calculus and Physics Teacher

W+L ≥ 692/2 = 346

L ≥ 346-W = 346-31 = 315 cm

Answer: The length of the rectangle must be at least 315 cm.

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.