The width of a rectangle is 31 centimeters. Find all possible values for the length of the rectangle if the perimeter is al least 692 centimerts

Question

I am trying to pull out equations from word problems

Answer 1

 P = 2L + 2W

 

P ≥ 692

 

 L+ W ≥ 346

 

  L+31≥ 346

 

 L ≥315

 

 

    This is simply an inequality problem.( ≥ ) should be used for at least ( minimum value),

 

   

Answer 2

In a rectangle opposite sides are equal

 

perimeter = 2(length + Width)

 

2(l + W) must greater than or equal to 692

L + W must be greater than or equal to (692/2)346

L + 31 must be greater than or equal to 346

there fore L must be greater than or equal to (346 - 31) 315

:)

 

 

Answer 3

Good morning! Recall that perimeter of a rectangle is the sum of the lengths of all sides, so:

 

P= L + L + W + W, or P + 2L + 2W

 

If the width is 31 and total perimeter is at least 692, then the minimum would be:

 

692 = 2L + 2(31), or 692 = 2L + 62

 

Subtract 62 from both sides:

 

630 = 2L

 

Divide both sides by 2:

 

315 = L

 

Remember that the perimeter is at least 692; therefore the length would be at least 315 cm

 

Hope this helps

 

Mike

Answer 4

W+L ≥ 692/2 = 346

L ≥ 346-W = 346-31 = 315 cm

 

Answer: The length of the rectangle must be at least 315 cm.