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# a triangle has a perimeter of 24 5/8 inches. what is the lenght of its third side 9 3/4 inches 7 1/3 inches

9 3/4 inches  7 1/3 inches need help with this problem

### 2 Answers by Expert Tutors

Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...
4.8 4.8 (4 lesson ratings) (4)
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c = 24 5/8 - 9 3/4 - 7 1/3 =

24 - 9 - 7 +5/8 - 3/4 - 8/3=

8  + 15 /24 -18 /24 -8 /24 =

8 - 11/24=  7 + 24/24 - 11/24 = 7 13/24

This is a hint how to handle addition of mixed numbers, you add integers together, and fractions together.
Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
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Hi Richard;

perimeter=(side A)+(side B)+(side C)
24 5/8=(9 3/4)+(7 1/3)+(side C)
Let's get rid of the fractions.
The denominators on the right side are 4 and 3.  Let's use the denominator of 12...
(3/4)(3/3)=9/12...side A 9 9/12
(1/3)(4/4)=4/12...side B 7 4/12
24 5/8=(9 9/12)+(7 4/12)+(side C)
24 5/8=(16 13/12)+(side C)
24 5/8=(17 1/12)+(side C)
The denominators are now 8 and 12.  Let's convert these to 24...
(5/8)(3/3)=15/24...perimeter=24 15/24
(1/12)(2/2)=2/24...sides A+B=17 2/24
24 15/24=(17 2/24)+(side C)
Let's move 17 2/24 from the right to the left side.  It becomes negative...
(24 15/24)-(17 2/24)=side C
7 13/24=side C