1. 5.00 g LiCl/ 95.0 g water
2. 100 g solution/ 5.00 g LiCl
3. 5.00 g LiCl/ 95.0 g solution
4. 95.0 g water/ 5.00 g LiCl
5. 95.0 g water/ 100 g solution
I have no idea, please tell me your reasoning! Thanks so much!
1. 5.00 g LiCl/ 95.0 g water
2. 100 g solution/ 5.00 g LiCl
3. 5.00 g LiCl/ 95.0 g solution
4. 95.0 g water/ 5.00 g LiCl
5. 95.0 g water/ 100 g solution
I have no idea, please tell me your reasoning! Thanks so much!
It appears to me all you need to focus on is that if the solution is 100 g this will be 5% LiCl, or 5.00 g LiCl, and 95% water, or 95.0 g water.
In summary, in a 100 g 5% aqueous solution of LiCl:
(i) solution, 100 g.
(ii) LiCl, 5.00 g.
(iii) water, 95.0 g.
Taking any one of these divided by another will yield a unit factor.
All but (3) are contructed correctly. The "95.0 g solution" is the problem.
Hope this helps.