What was the rat population in 1994?

What is the rat population going to be in the year 2005?

What was the rat population in 1994?

What is the rat population going to be in the year 2005?

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Aliquippa, PA

n(t) = 67e^{0.035t}

In 1994 the rat population was 67,000,000 because any number times e^{0} = that number (i.e. e^{0} = 1)

The year 2005 was 11 years after 1994, so t = 11 years.

n(t) = 67*[e^{(0.035)(11 years)}]

Spanaway, WA

Assuming the initial rat population was 67 million, simply plug in 11 for t, so:

2005-1994 = 11; Eleven years have passed.

0.035 * t = 0.035 * 11 = 0.385;

n(11) = 67 * e^{(0.035*11)}

n(11) = 67 * e^{0.385 }= 67 * 1.46961 = 98.4641 (million)

1.) In windows calculator, use View>Scientific view

2.) For e^{x }use [Inv]. This changes the [ln] button to [e^{x}].

3.) Multiply by 67.

.385 [Inv][e^{x}] or [Inv][ln] or [Inv][log] on your calculator, then times 67.

e = 2.7182... > 1. So with a positive exponent, the result will also be >1. The more years pass, the greater the exponent,and the greater the result (and number of rats) will be. When you multiply by a number greater than one, the result will always be a bigger number.

Hallandale, FL

Before 1994, n(0) = 67

In year 1994, n(1) = 67e^{0.035} ≈ 67 * 1.03562 ≈ 69.386520

In year 2005, n(12) = 67e^{0.035*12} ≈ 67 * 1.521962 ≈ 101.9714242

*The rat population in 1994 was ≈ 69,386,520*

*The rat population in 2005 going to be ≈ 101,971,424 *

In year 1994, n(1) = 67e

In year 2005, n(12) = 67e

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