thanks guys!!! i appreciate your help so much :)

a^2 ± 2ab + b^2 = (a ± b)^2

x^2 + 5x - 5 = 0

(x^2 + 2*(5/2)x + 25/4) - 25/4 - 20/4 = 0

(x + 5/2)^2 = 45/4

x + (5/2) = ± √(45/4)

1). x + 5/2 = (3√5)/2

2). x + 5/2 = - (3√5)/2

x^2 + 5x - 5 = 0

(x^2 + 2*(5/2)x + 25/4) - 25/4 - 20/4 = 0

(x + 5/2)^2 = 45/4

x + (5/2) = ± √(45/4)

1). x + 5/2 = (3√5)/2

*x*_{1}= [(3√5) - 5] / 22). x + 5/2 = - (3√5)/2

*x*_{2}= - [(3√5) + 5] / 2
## Comments

Good solution Nataliya.