y^3-14y^2+48y=

Or is it prime?

y^3-14y^2+48y=

Or is it prime?

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Middletown, CT

Hi again Bridget;

Now let's do the equation!

y^{3}-14y^{2}+48y=

For the FOIL...

FIRST must be...(y^{2})(y)=y^{3}

OUTER and INNER must add-up to -14y^{2}

LAST must be (8)(6y) or (8y)(6) or (24)(2y) or (24y)(2) or (16y)(3) or (16)(3), etc. and both numbers must be negative.

(y^{2}-6y)(y-8)

Let's FOIL...

FIRST...(y^{2})(y)=y^{3}^{
}

OUTER...(y^{2})(8)=-8y^{2}

INNER...(6y)(y)=-6y^{2}

LAST...(-6y)(-8)=48y

y^{3}-8y^{2-}6y^{2}+48y

y^{3}-14y^{2}+48y

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