
Bob F. answered 03/08/16
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I will do Question 1. Follow the same procedure and you should be able to do Question 2 and Question 3.
First, write the balanced equation for the titration reaction:
Ba(OH)2 + 2HCl → 2 BaCl + 2 H2O
At the equivalence point for this reaction, the number of moles of OH- delivered neutralized an equivalent number of moles of H+
and the relationship M1V1 = M2V2 is followed.
Using the stoichiometry of the reaction, solve for M2:
23.46 mL Ba(OH)2 x (1L/1000 mL) x .00325 mole Ba(OH)2/L x (2 mole OH-/mole Ba(OH)2) x (2 mole HCl/ 2 mole OH-) x (1/13.8 mL HCl) x 1000 mL HCl/L HCl) = 0.011 M HCl
∴ the concentration of the HCl is 0.011 M