The equation for this problem goes something like this, temperature at noon=37-(2x6)+(4x20), which equals 105 degrees Fahrenheit.
37 degrees is that starting temperature, and from 10 to 4 is a 6 hour difference. Therefore since there is drop of 2 degrees every hour, we multiply 2 by 6, obtaining 12. We then subtract this value since the temperature is dropping.
The next step is a rise of 4 degrees every hour, and from 4PM to 12PM the next day there is a 20 hour difference. Therefore, we multiply 4 by 20 to get 80. We add this value because the temperature is rising.
In the end, we get 105 degrees as the temperature at 12PM the next day.