combination or permutation?

There are 13 clubs and 39 cards of other suits.

If you want exactly one club:

C(13,1)*C(39,6) = 42414099

If you want at least one club:

C(52,7) - # of hands with no clubs = C(52,7) - C(39,7) = 130521937

combination or permutation?

Tutors, please sign in to answer this question.

There are 13 clubs and 39 cards of other suits.

If you want exactly one club:

C(13,1)*C(39,6) = 42414099

If you want at least one club:

C(52,7) - # of hands with no clubs = C(52,7) - C(39,7) = 130521937

Malik K.

MIT Grad, Math/Physics Tutor, Summer Math/Engineering Camp Instructor

New York, NY

5.0
(16 ratings)

Romina A.

Knowledgeable tutor in Spanish, Biology, Anatomy & Physiology and Math

Harrison, NJ

5.0
(72 ratings)

Evan F.

Mathematics graduate looking to enhance your mathematics ability.

Richmond Hill, NY

4.9
(195 ratings)