^{2}+8x-69=0 Solve by factoring?

**So the solutions are x=3, x=-23/5**

5x^{2}+8x-69=0 Solve by factoring?

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John M. | John - Algebra TutorJohn - Algebra Tutor

Factoring the equation:

5 is a prime number, the middle term is positive and the final term is negative, and it's a second degree equation, so we know we have 2 terms, with opposite signs and a 5 and 1 as the x coefficients:

(5x+ )(x- )

next we must find the factors of 69. 1&69 don't work because they don't subtract to get 8. However 3 and 23 work because:

23-5(3)=8. This also tells us that we must end up with a -15 during the FOIL. So we know that the signs of the constants must be changed and gives us the factors:

(5x+23)(x-3)=0

To solve for the values of x that make this equation true we set each term equal to 0 and solve them separately.

5x+23=0 and x-3 = 0

The second is simply a matter of adding 3 to both sides and we get x=3.

The first is 2 operations, subtract 23 from both sides and divide both by 5 and we get x=-23/5

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