5x

^{2}+8x-69=0 Solve by factoring?5x^{2}+8x-69=0 Solve by factoring?

Tutors, please sign in to answer this question.

Toney, AL

Factoring the equation:

5 is a prime number, the middle term is positive and the final term is negative, and it's a second degree equation, so we know we have 2 terms, with opposite signs and a 5 and 1 as the x coefficients:

(5x+ )(x- )

next we must find the factors of 69. 1&69 don't work because they don't subtract to get 8. However 3 and 23 work because:

23-5(3)=8. This also tells us that we must end up with a -15 during the FOIL. So we know that the signs of the constants must be changed and gives us the factors:

(5x+23)(x-3)=0

To solve for the values of x that make this equation true we set each term equal to 0 and solve them separately.

5x+23=0 and x-3 = 0

The second is simply a matter of adding 3 to both sides and we get x=3.

The first is 2 operations, subtract 23 from both sides and divide both by 5 and we get x=-23/5

Larry G.

Algebra/Geometry/SAT Tutor

Bronx, NY

4.9
(138 ratings)

John K.

Ardent Mathematics, Science, History, SAT and German Polymath

College Point, NY

5.0
(50 ratings)

John E.

Physics and Math tutor - Masters from Cornell and Columbia University

New York, NY

4.8
(124 ratings)

- Algebra 2 2689
- Algebra 3765
- Math 6771
- Prealgebra 141
- Geometry 1371
- Algebra Help 868
- Algebra Word Problem 1909
- Math Help 3983
- Word Problem 3751
- Precalculus 1206

Find a tutor fast. Get the app.

Are you a tutor? Get the app for tutors

© 2005 - 2016 WyzAnt, Inc. - All Rights Reserved