this is solve for x

if this was the equation:

3

^{x}+3^{x}+1=36then:

2(3

^{x}) +1=362(3

^{x})=353

^{x}=35/2x=log

_{3}(35/2)x=log

_{3}(35) - log_{3}(2)if this was the equation:

3

^{x}+ 3^{x+1}= 36then:

3

^{x + }3(3^{x}) = 363

^{x}(3+1) = 363

^{x}= 36/43

^{x}= 9x = log

_{3}9x=2

(since this is a much nicer answer, I'm inclined to believe this is what you meant)

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