^{2}- 2y)

^{2}- 2x).

^{2}- 2x, which is x(x-2). And we know that denominators cannot be zero (or else the function is "undefined"). So this means that the value(s) of x that make(s) the function undefined is when...

f(x)= y+2/y^2-2y

the domain of the function is ?

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Rodrigo V. | MS/HS/College Level Chemistry and Math tutorMS/HS/College Level Chemistry and Math t...

David,

f(x) means that the function is in terms of x, but you're saying that the function f(x) is:

f(x) = (y+2)/(y^{2} - 2y)

which is in terms of y. So it should be either f(y) or f(x) = (x+2)/(x^{2} - 2x).

Domain, by definition, is a set of values in which the function is "defined".

First, factor the denominator x^{2} - 2x, which is x(x-2). And we know that denominators cannot be zero (or else the function is "undefined"). So this means that the value(s) of x that make(s) the function undefined is when...

x(x-2) = 0

This is true when x = 2 and when x = 0.

So the domain of the function is all values of x except when x = {0,2}. To write this is notation form D = (-infinity∪0∪2∪infinity).

I hope that helps! :)

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