Eric C. answered 12/03/15
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Engineer, Surfer Dude, Football Player, USC Alum, Math Aficionado
Hi Tiara.
The pencil is a height of 2.5m off the ground and will immediately be effected by gravity on its fall. We can use this fact to determine how long the pencil was in the air.
h = 1/2*g*t^2
2.5 = 1/2*9.8*t^2
5 = 9.8*t^2
t^2 = 0.51
t = 0.71 seconds
The horizontal component of travel is constant. We know it was traveling 10m/s initially from the question, and based on the height from which it fell and gravity, we determined it was in the air for 0.71 seconds.
distance = rate*time
= 10m/s * 0.71 seconds = 7.1 meters.
That is a speedy pencil.