C(x)= 1/x^2-4

the domain is

answer in interval notation

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Hi Bridget, set the the denominator of

x^2-4 0

+4 +4

x^2 ≠ 4

sqrt(x^2) ≠
sqrt(4)

x = ±2

So, the domain of the function will be

{x|x ≠ -2, x ≠ 2} and in interval notation (-∞,-2)U(-2,2)U(2,∞)

Hi Bridget;

C(x)= 1/x^2-4

I believe this is...

C(x)=1/(x^{2}-4)

You probably already know that a numerator cannot equal zero.

So let's work with 0≠x^{2}-4

Let's factor...

0≠(x-2)(x+2)

Let's separate...

0≠x-2 and 0≠x+2

x≠2 and 0≠-2

The domain is all integers except -2 and 2.

(-infinity,-2)U(-2,2)U(2, +infinity)

According to Michael F., the Wyant of Wilton, CT, "the parentheses ( and ) indicate no endpoints. The symbol ∪ means set union."

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