^{2 }+16x = -8

^{2}+ 16x + 64 = -8 + 64

^{2}= 56

What value should you add to each side of the equation?

x^2+16x=-8

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James H. | Math Tutor and Educational ConsultantMath Tutor and Educational Consultant

x^{2 }+16x = -8

Add 64 to both sides: x^{2} + 16x + 64 = -8 + 64

Factor and simplify: (x + 8)^{2} = 56

Use the square root method: x + 8 = ± √(56)

Subtract 8 from both sides: x = -8 ± √(56)

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