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# Write the equation of the line which passes through (–4, 2) and is parallel to y = –x + 6 in slope-intercept form

I'm not understanding this at all, Write the equation of the line which passes through (–4, 2) and is parallel to y = –x + 6 in slope-intercept form

### 2 Answers by Expert Tutors

Bill F. | Best Math Tutor in the AreaBest Math Tutor in the Area
5.0 5.0 (238 lesson ratings) (238)
3
Hi Hannah,

They gave you a line (y = -x + 6) which has a slope of -1 (the number in front of the x when the equation is in the form of y = mx + b; in other words, the "m").

Another line (the one you are about to find the equation for) is parallel to the above line.  That means the line has the SAME slope, -1.

Now, use the formula y - y1 = m(x - x1) to solve for your answer (x1 and y1 come from the point (-4, 2) ):

So,  y - 2 = -1(x - -4)

Remember that - -4 is really +4.  After you distribute the -1 you get:

y - 2 = -x - 4
+2        +2

y = -x - 2

Bill Fanning
El Paso TX
Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...
4.8 4.8 (4 lesson ratings) (4)
-1
Always write equation of line :

Y = mX + b   , and then find values of m, b.

It is parallel with  line Y = - X + 6

there for m = -1

Y = -X + b '

Passes through ( - 4 , 2) , therefore ( -4, 2 ) must be a point on line, and the coordinates should be plugged in the equation:
2 = - 4 + b , then    b =6

The answer is     Y= -X + 6