If I have 3 in the first group and you add 2 more each group how many will be in group 100

you begin with 3 and add 2 ninety-nine times

3+(99*2)=3+198=201

If I have 3 in the first group and you add 2 more each group how many will be in group 100

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Saugus, MA

you begin with 3 and add 2 ninety-nine times

3+(99*2)=3+198=201

Suisun City, CA

G(1) = 3

G(2) = 3 + 2(1)

G(3) = 3 + 2(2)

G(4) = 3 + 2(3)

.

.

.

G(n) = 3 + 2(n-1)

hence,

G(100) = 3 + 2(100-1) = 201

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